Base | Representation |
---|---|
bin | 11101100101110011100001… |
… | …111110001110010101101101 |
3 | 122001210101102222100220202211 |
4 | 131211303201332032111231 |
5 | 114024213340331112221 |
6 | 1140442031000450421 |
7 | 36261253512100105 |
oct | 3545634176162555 |
9 | 561711388326684 |
10 | 130141300254061 |
11 | 385156852424a8 |
12 | 1271a30a179a11 |
13 | 578036c640985 |
14 | 241cc30376205 |
15 | 100a41950a6e1 |
hex | 765ce1f8e56d |
130141300254061 has 2 divisors, whose sum is σ = 130141300254062. Its totient is φ = 130141300254060.
The previous prime is 130141300254013. The next prime is 130141300254083. The reversal of 130141300254061 is 160452003141031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 106750100016036 + 23391200238025 = 10331994^2 + 4836445^2 .
It is a cyclic number.
It is not a de Polignac number, because 130141300254061 - 237 = 130003861300589 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130141300254001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65070650127030 + 65070650127031.
It is an arithmetic number, because the mean of its divisors is an integer number (65070650127031).
Almost surely, 2130141300254061 is an apocalyptic number.
It is an amenable number.
130141300254061 is a deficient number, since it is larger than the sum of its proper divisors (1).
130141300254061 is an equidigital number, since it uses as much as digits as its factorization.
130141300254061 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 130141300254061 its reverse (160452003141031), we get a palindrome (290593303395092).
The spelling of 130141300254061 in words is "one hundred thirty trillion, one hundred forty-one billion, three hundred million, two hundred fifty-four thousand, sixty-one".
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