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130141300254061 is a prime number
BaseRepresentation
bin11101100101110011100001…
…111110001110010101101101
3122001210101102222100220202211
4131211303201332032111231
5114024213340331112221
61140442031000450421
736261253512100105
oct3545634176162555
9561711388326684
10130141300254061
11385156852424a8
121271a30a179a11
13578036c640985
14241cc30376205
15100a41950a6e1
hex765ce1f8e56d

130141300254061 has 2 divisors, whose sum is σ = 130141300254062. Its totient is φ = 130141300254060.

The previous prime is 130141300254013. The next prime is 130141300254083. The reversal of 130141300254061 is 160452003141031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106750100016036 + 23391200238025 = 10331994^2 + 4836445^2 .

It is a cyclic number.

It is not a de Polignac number, because 130141300254061 - 237 = 130003861300589 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130141300254001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65070650127030 + 65070650127031.

It is an arithmetic number, because the mean of its divisors is an integer number (65070650127031).

Almost surely, 2130141300254061 is an apocalyptic number.

It is an amenable number.

130141300254061 is a deficient number, since it is larger than the sum of its proper divisors (1).

130141300254061 is an equidigital number, since it uses as much as digits as its factorization.

130141300254061 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 130141300254061 its reverse (160452003141031), we get a palindrome (290593303395092).

The spelling of 130141300254061 in words is "one hundred thirty trillion, one hundred forty-one billion, three hundred million, two hundred fifty-four thousand, sixty-one".