Base | Representation |
---|---|
bin | 11101100101110101001111… |
… | …000010001100101100000101 |
3 | 122001210120011111101021100222 |
4 | 131211311033002030230011 |
5 | 114024231112240344141 |
6 | 1140442532322514125 |
7 | 36261350040555431 |
oct | 3545651702145405 |
9 | 561716144337328 |
10 | 130143130012421 |
11 | 38516434081a99 |
12 | 1271a73ab05945 |
13 | 57805a174ca26 |
14 | 241cd653979c1 |
15 | 100a4c4e9114b |
hex | 765d4f08cb05 |
130143130012421 has 4 divisors (see below), whose sum is σ = 130166676811872. Its totient is φ = 130119583212972.
The previous prime is 130143130012393. The next prime is 130143130012429. The reversal of 130143130012421 is 124210031341031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130143130012421 is a prime.
It is a super-2 number, since 2×1301431300124212 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130143130012429) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11773391435 + ... + 11773402488.
It is an arithmetic number, because the mean of its divisors is an integer number (32541669202968).
Almost surely, 2130143130012421 is an apocalyptic number.
It is an amenable number.
130143130012421 is a deficient number, since it is larger than the sum of its proper divisors (23546799451).
130143130012421 is an equidigital number, since it uses as much as digits as its factorization.
130143130012421 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23546799450.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 130143130012421 its reverse (124210031341031), we get a palindrome (254353161353452).
The spelling of 130143130012421 in words is "one hundred thirty trillion, one hundred forty-three billion, one hundred thirty million, twelve thousand, four hundred twenty-one".
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