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130145015203439 = 263572238647711
BaseRepresentation
bin11101100101110110111111…
…011001101000011001101111
3122001210202000212200220021112
4131211312333121220121233
5114024243442343002224
61140443443345022235
736261444541456235
oct3545667731503157
9561722025626245
10130145015203439
11385172112329a5
121271ab8632497b
135780812199b82
14241d0a38c8955
15100a58572630e
hex765dbf66866f

130145015203439 has 8 divisors (see below), whose sum is σ = 130642161272832. Its totient is φ = 129647886544440.

The previous prime is 130145015203433. The next prime is 130145015203471. The reversal of 130145015203439 is 934302510541031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130145015203439 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130145015203396 and 130145015203405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130145015203433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10725794 + ... + 19373504.

It is an arithmetic number, because the mean of its divisors is an integer number (16330270159104).

Almost surely, 2130145015203439 is an apocalyptic number.

130145015203439 is a deficient number, since it is larger than the sum of its proper divisors (497146069393).

130145015203439 is an equidigital number, since it uses as much as digits as its factorization.

130145015203439 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8705197.

The product of its (nonzero) digits is 194400, while the sum is 41.

The spelling of 130145015203439 in words is "one hundred thirty trillion, one hundred forty-five billion, fifteen million, two hundred three thousand, four hundred thirty-nine".

Divisors: 1 263 57223 8647711 15049649 2274347993 494847966553 130145015203439