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130146325017345 = 325713127409361141
BaseRepresentation
bin11101100101111000001101…
…011110001011001100000001
3122001210212102011100100011200
4131211320031132023030001
5114024304133201023340
61140444221334531413
736261522154632540
oct3545701536131401
9561725364310150
10130146325017345
113851782362352a
121271b290b06b69
13578099065caa0
14241d189842157
15100a610704330
hex765e0d78b301

130146325017345 has 192 divisors, whose sum is σ = 279904624656384. Its totient is φ = 54472253552640.

The previous prime is 130146325017341. The next prime is 130146325017437. The reversal of 130146325017345 is 543710523641031.

130146325017345 is a `hidden beast` number, since 1 + 3 + 0 + 1 + 4 + 6 + 32 + 501 + 73 + 45 = 666.

It is not a de Polignac number, because 130146325017345 - 22 = 130146325017341 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 130146325017345.

It is not an unprimeable number, because it can be changed into a prime (130146325017341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 2128595475 + ... + 2128656615.

It is an arithmetic number, because the mean of its divisors is an integer number (1457836586752).

Almost surely, 2130146325017345 is an apocalyptic number.

130146325017345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

130146325017345 is an abundant number, since it is smaller than the sum of its proper divisors (149758299639039).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130146325017345 is a wasteful number, since it uses less digits than its factorization.

130146325017345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65392 (or 65389 counting only the distinct ones).

The product of its (nonzero) digits is 907200, while the sum is 45.

Adding to 130146325017345 its reverse (543710523641031), we get a palindrome (673856848658376).

The spelling of 130146325017345 in words is "one hundred thirty trillion, one hundred forty-six billion, three hundred twenty-five million, seventeen thousand, three hundred forty-five".