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13014803117 is a prime number
BaseRepresentation
bin11000001111011111…
…00010001010101101
31020121000122111112002
430013233202022231
5203123242144432
65551240222045
7640343000261
oct140757421255
936530574462
1013014803117
115579576238
12263276a925
1312c5485844
148b67000a1
155128c7e62
hex307be22ad

13014803117 has 2 divisors, whose sum is σ = 13014803118. Its totient is φ = 13014803116.

The previous prime is 13014803059. The next prime is 13014803147. The reversal of 13014803117 is 71130841031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12773746441 + 241056676 = 113021^2 + 15526^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13014803117 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13014803117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13014803147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6507401558 + 6507401559.

It is an arithmetic number, because the mean of its divisors is an integer number (6507401559).

Almost surely, 213014803117 is an apocalyptic number.

It is an amenable number.

13014803117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13014803117 is an equidigital number, since it uses as much as digits as its factorization.

13014803117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 29.

The spelling of 13014803117 in words is "thirteen billion, fourteen million, eight hundred three thousand, one hundred seventeen".