1301500111 has 2 divisors, whose sum is σ = 1301500112. Its totient is φ = 1301500110.

The previous prime is 1301500097. The next prime is 1301500121. The reversal of 1301500111 is 1110051031.

It is a strong prime.

It is an emirp because it is prime and its reverse (1110051031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1301500111 - 2¹¹ = 1301498063 is a prime.

It is a super-3 number, since 3×1301500111³ (a number of 28 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1301500091 and 1301500100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301500121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650750055 + 650750056.

It is an arithmetic number, because the mean of its divisors is an integer number (650750056).

Almost surely, 2^1301500111 is an apocalyptic number.

1301500111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301500111 is an equidigital number, since it uses as much as digits as its factorization.

1301500111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 13.

The square root of 1301500111 is about 36076.3095535006. The cubic root of 1301500111 is about 1091.8125192482.

Adding to 1301500111 its reverse (1110051031), we get a palindrome (2411551142).

The spelling of 1301500111 in words is "one billion, three hundred one million, five hundred thousand, one hundred eleven".