Base | Representation |
---|---|
bin | 11101100101111111011000… |
… | …001100011110100000001111 |
3 | 122001211121021111220212022022 |
4 | 131211333120030132200033 |
5 | 114024420413401320030 |
6 | 1140451533141040355 |
7 | 36262213655501624 |
oct | 3545773014364017 |
9 | 561747244825268 |
10 | 130154021120015 |
11 | 385200128a5362 |
12 | 1272087a3b60bb |
13 | 5781618c3c1a9 |
14 | 241d6b9a0034b |
15 | 100a9111c0de5 |
hex | 765fd831e80f |
130154021120015 has 4 divisors (see below), whose sum is σ = 156184825344024. Its totient is φ = 104123216896008.
The previous prime is 130154021119979. The next prime is 130154021120033. The reversal of 130154021120015 is 510021120451031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130154021120015 - 218 = 130154020857871 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13015402111997 + ... + 13015402112006.
It is an arithmetic number, because the mean of its divisors is an integer number (39046206336006).
Almost surely, 2130154021120015 is an apocalyptic number.
130154021120015 is a deficient number, since it is larger than the sum of its proper divisors (26030804224009).
130154021120015 is an equidigital number, since it uses as much as digits as its factorization.
130154021120015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26030804224008.
The product of its (nonzero) digits is 1200, while the sum is 26.
Adding to 130154021120015 its reverse (510021120451031), we get a palindrome (640175141571046).
The spelling of 130154021120015 in words is "one hundred thirty trillion, one hundred fifty-four billion, twenty-one million, one hundred twenty thousand, fifteen".
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