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130160521123799 is a prime number
BaseRepresentation
bin11101100110000101011011…
…101000000001011111010111
3122001212020001111211021020012
4131212011123220001133113
5114030022221401430144
61140454530134430435
736262534023561155
oct3546053350013727
9561766044737205
10130160521123799
1138522848995411
1212721b9320241b
13578211379198a
14241db34da63d5
15100ab91b72e9e
hex76615ba017d7

130160521123799 has 2 divisors, whose sum is σ = 130160521123800. Its totient is φ = 130160521123798.

The previous prime is 130160521123781. The next prime is 130160521123807. The reversal of 130160521123799 is 997321125061031.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130160521123799 - 216 = 130160521058263 is a prime.

It is a super-2 number, since 2×1301605211237992 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130160521123709) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65080260561899 + 65080260561900.

It is an arithmetic number, because the mean of its divisors is an integer number (65080260561900).

Almost surely, 2130160521123799 is an apocalyptic number.

130160521123799 is a deficient number, since it is larger than the sum of its proper divisors (1).

130160521123799 is an equidigital number, since it uses as much as digits as its factorization.

130160521123799 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 612360, while the sum is 50.

The spelling of 130160521123799 in words is "one hundred thirty trillion, one hundred sixty billion, five hundred twenty-one million, one hundred twenty-three thousand, seven hundred ninety-nine".