Base | Representation |
---|---|
bin | 111100100111010001… |
… | …0001101101000010001 |
3 | 110102222112102221012012 |
4 | 1321032202031220101 |
5 | 4113040123013244 |
6 | 135444150112305 |
7 | 12255435635051 |
oct | 1711642155021 |
9 | 412875387165 |
10 | 130166610449 |
11 | 50226727017 |
12 | 2128864b695 |
13 | c37556b0b5 |
14 | 642b679561 |
15 | 35bc7c489e |
hex | 1e4e88da11 |
130166610449 has 2 divisors, whose sum is σ = 130166610450. Its totient is φ = 130166610448.
The previous prime is 130166610439. The next prime is 130166610451. The reversal of 130166610449 is 944016661031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 77894019025 + 52272591424 = 279095^2 + 228632^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130166610449 is a prime.
Together with 130166610451, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (130166610439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65083305224 + 65083305225.
It is an arithmetic number, because the mean of its divisors is an integer number (65083305225).
Almost surely, 2130166610449 is an apocalyptic number.
It is an amenable number.
130166610449 is a deficient number, since it is larger than the sum of its proper divisors (1).
130166610449 is an equidigital number, since it uses as much as digits as its factorization.
130166610449 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 93312, while the sum is 41.
The spelling of 130166610449 in words is "one hundred thirty billion, one hundred sixty-six million, six hundred ten thousand, four hundred forty-nine".
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