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130166610449 is a prime number
BaseRepresentation
bin111100100111010001…
…0001101101000010001
3110102222112102221012012
41321032202031220101
54113040123013244
6135444150112305
712255435635051
oct1711642155021
9412875387165
10130166610449
1150226727017
122128864b695
13c37556b0b5
14642b679561
1535bc7c489e
hex1e4e88da11

130166610449 has 2 divisors, whose sum is σ = 130166610450. Its totient is φ = 130166610448.

The previous prime is 130166610439. The next prime is 130166610451. The reversal of 130166610449 is 944016661031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77894019025 + 52272591424 = 279095^2 + 228632^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130166610449 is a prime.

Together with 130166610451, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130166610439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65083305224 + 65083305225.

It is an arithmetic number, because the mean of its divisors is an integer number (65083305225).

Almost surely, 2130166610449 is an apocalyptic number.

It is an amenable number.

130166610449 is a deficient number, since it is larger than the sum of its proper divisors (1).

130166610449 is an equidigital number, since it uses as much as digits as its factorization.

130166610449 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 41.

The spelling of 130166610449 in words is "one hundred thirty billion, one hundred sixty-six million, six hundred ten thousand, four hundred forty-nine".