Base | Representation |
---|---|
bin | 100110110011011… |
… | …0010000100111111 |
3 | 10100201222001222221 |
4 | 1031212302010333 |
5 | 10131303342343 |
6 | 333110350211 |
7 | 44156631001 |
oct | 11546620477 |
9 | 3321861887 |
10 | 1302012223 |
11 | 608a52066 |
12 | 30405b367 |
13 | 179990b45 |
14 | c4cc6371 |
15 | 7948b5ed |
hex | 4d9b213f |
1302012223 has 2 divisors, whose sum is σ = 1302012224. Its totient is φ = 1302012222.
The previous prime is 1302012211. The next prime is 1302012241. The reversal of 1302012223 is 3222102031.
It is a weak prime.
It is an emirp because it is prime and its reverse (3222102031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1302012223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1302012197 and 1302012206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1302012253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651006111 + 651006112.
It is an arithmetic number, because the mean of its divisors is an integer number (651006112).
Almost surely, 21302012223 is an apocalyptic number.
1302012223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302012223 is an equidigital number, since it uses as much as digits as its factorization.
1302012223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 16.
The square root of 1302012223 is about 36083.4064772161. The cubic root of 1302012223 is about 1091.9557019671.
Adding to 1302012223 its reverse (3222102031), we get a palindrome (4524114254).
The spelling of 1302012223 in words is "one billion, three hundred two million, twelve thousand, two hundred twenty-three".
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