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1302020494357 = 11191619714657
BaseRepresentation
bin10010111100100110011…
…110000001010000010101
311121110202001021012102111
4102330212132001100111
5132313014221304412
62434050121511021
7163032165411442
oct22744636012025
94543661235374
101302020494357
11462202697540
12190410042471
1395a1a898c2b
1447037a5a9c9
1523d064d52a7
hex12f26781415

1302020494357 has 8 divisors (see below), whose sum is σ = 1427822572032. Its totient is φ = 1177457846400.

The previous prime is 1302020494351. The next prime is 1302020494361. The reversal of 1302020494357 is 7534940202031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1302020494357 - 211 = 1302020492309 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1302020494351) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 309855228 + ... + 309859429.

It is an arithmetic number, because the mean of its divisors is an integer number (178477821504).

Almost surely, 21302020494357 is an apocalyptic number.

It is an amenable number.

1302020494357 is a deficient number, since it is larger than the sum of its proper divisors (125802077675).

1302020494357 is a wasteful number, since it uses less digits than its factorization.

1302020494357 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 619714859.

The product of its (nonzero) digits is 181440, while the sum is 40.

Adding to 1302020494357 its reverse (7534940202031), we get a palindrome (8836960696388).

The spelling of 1302020494357 in words is "one trillion, three hundred two billion, twenty million, four hundred ninety-four thousand, three hundred fifty-seven".

Divisors: 1 11 191 2101 619714657 6816861227 118365499487 1302020494357