130203033300131 has 4 divisors (see below), whose sum is σ = 142039672691064. Its totient is φ = 118366393909200.

The previous prime is 130203033300091. The next prime is 130203033300203. The reversal of 130203033300131 is 131003330302031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130203033300131 is a prime.

It is a super-2 number, since 2×130203033300131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130203033300097 and 130203033300106.

It is not an unprimeable number, because it can be changed into a prime (130203033303131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5918319695450 + ... + 5918319695471.

It is an arithmetic number, because the mean of its divisors is an integer number (35509918172766).

Almost surely, 2^{130203033300131} is an apocalyptic number.

130203033300131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

130203033300131 is a deficient number, since it is larger than the sum of its proper divisors (11836639390933).

130203033300131 is a wasteful number, since it uses less digits than its factorization.

130203033300131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11836639390932.

The product of its (nonzero) digits is 1458, while the sum is 23.

Adding to 130203033300131 its reverse (131003330302031), we get a palindrome (261206363602162).

The spelling of 130203033300131 in words is "one hundred thirty trillion, two hundred three billion, thirty-three million, three hundred thousand, one hundred thirty-one".