Base | Representation |
---|---|
bin | 11101100110101101001011… |
… | …100011001101100110111111 |
3 | 122002000022012221201201020202 |
4 | 131212231023203031212333 |
5 | 114031222123440201343 |
6 | 1140530305210434115 |
7 | 36265604462440256 |
oct | 3546551343154677 |
9 | 562008187651222 |
10 | 130203201100223 |
11 | 3853995a6a33a9 |
12 | 1272a30473293b |
13 | 5786155b398b4 |
14 | 2421c2347379d |
15 | 100bd3da86db8 |
hex | 766b4b8cd9bf |
130203201100223 has 2 divisors, whose sum is σ = 130203201100224. Its totient is φ = 130203201100222.
The previous prime is 130203201100211. The next prime is 130203201100243. The reversal of 130203201100223 is 322001102302031.
It is an a-pointer prime, because the next prime (130203201100243) can be obtained adding 130203201100223 to its sum of digits (20).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130203201100223 - 232 = 130198906132927 is a prime.
It is a super-2 number, since 2×1302032011002232 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130203201100195 and 130203201100204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130203201100243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65101600550111 + 65101600550112.
It is an arithmetic number, because the mean of its divisors is an integer number (65101600550112).
Almost surely, 2130203201100223 is an apocalyptic number.
130203201100223 is a deficient number, since it is larger than the sum of its proper divisors (1).
130203201100223 is an equidigital number, since it uses as much as digits as its factorization.
130203201100223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 130203201100223 its reverse (322001102302031), we get a palindrome (452204303402254).
The spelling of 130203201100223 in words is "one hundred thirty trillion, two hundred three billion, two hundred one million, one hundred thousand, two hundred twenty-three".
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