Base | Representation |
---|---|
bin | 11101100110101101111100… |
… | …011100011010100110100110 |
3 | 122002000101100010021100202212 |
4 | 131212231330130122212212 |
5 | 114031230313434331042 |
6 | 1140530522432403422 |
7 | 36265634013050561 |
oct | 3546557434324646 |
9 | 562011303240685 |
10 | 130204021402022 |
11 | 3853a240740277 |
12 | 1272a4b33a6572 |
13 | 5786256a7a389 |
14 | 2421ca03a54d8 |
15 | 100bd8aabe482 |
hex | 766b7c71a9a6 |
130204021402022 has 4 divisors (see below), whose sum is σ = 195306032103036. Its totient is φ = 65102010701010.
The previous prime is 130204021401953. The next prime is 130204021402027. The reversal of 130204021402022 is 220204120402031.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130204021402027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32551005350504 + ... + 32551005350507.
It is an arithmetic number, because the mean of its divisors is an integer number (48826508025759).
Almost surely, 2130204021402022 is an apocalyptic number.
130204021402022 is a deficient number, since it is larger than the sum of its proper divisors (65102010701014).
130204021402022 is an equidigital number, since it uses as much as digits as its factorization.
130204021402022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65102010701013.
The product of its (nonzero) digits is 1536, while the sum is 23.
Adding to 130204021402022 its reverse (220204120402031), we get a palindrome (350408141804053).
Subtracting 130204021402022 from its reverse (220204120402031), we obtain a palindrome (90000099000009).
The spelling of 130204021402022 in words is "one hundred thirty trillion, two hundred four billion, twenty-one million, four hundred two thousand, twenty-two".
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