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130204402032 = 2432712591709
BaseRepresentation
bin111100101000011001…
…0011000000101110000
3110110002011112221111110
41321100302120011300
54113124311331112
6135452020113320
712256405104435
oct1712062300560
9413064487443
10130204402032
1150245a99431
1221299235840
13c380340693
1464326b5b8c
1535c0c8c13c
hex1e50c98170

130204402032 has 20 divisors (see below), whose sum is σ = 336361372040. Its totient is φ = 43401467328.

The previous prime is 130204401991. The next prime is 130204402051. The reversal of 130204402032 is 230204402031.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1356295807 + ... + 1356295902.

It is an arithmetic number, because the mean of its divisors is an integer number (16818068602).

Almost surely, 2130204402032 is an apocalyptic number.

130204402032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

130204402032 is an abundant number, since it is smaller than the sum of its proper divisors (206156970008).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130204402032 is a wasteful number, since it uses less digits than its factorization.

130204402032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2712591720 (or 2712591714 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 21.

Adding to 130204402032 its reverse (230204402031), we get a palindrome (360408804063).

Subtracting 130204402032 from its reverse (230204402031), we obtain a palindrome (99999999999).

The spelling of 130204402032 in words is "one hundred thirty billion, two hundred four million, four hundred two thousand, thirty-two".

Divisors: 1 2 3 4 6 8 12 16 24 48 2712591709 5425183418 8137775127 10850366836 16275550254 21700733672 32551100508 43401467344 65102201016 130204402032