130210212113 has 4 divisors (see below), whose sum is σ = 134410541568. Its totient is φ = 126009882660.

The previous prime is 130210212089. The next prime is 130210212241. The reversal of 130210212113 is 311212012031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130210212113 - 2⁶ = 130210212049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 130210212091 and 130210212100.

It is not an unprimeable number, because it can be changed into a prime (130210212313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2100164681 + ... + 2100164742.

It is an arithmetic number, because the mean of its divisors is an integer number (33602635392).

Almost surely, 2^130210212113 is an apocalyptic number.

It is an amenable number.

130210212113 is a deficient number, since it is larger than the sum of its proper divisors (4200329455).

130210212113 is an equidigital number, since it uses as much as digits as its factorization.

130210212113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4200329454.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 130210212113 its reverse (311212012031), we get a palindrome (441422224144).

The spelling of 130210212113 in words is "one hundred thirty billion, two hundred ten million, two hundred twelve thousand, one hundred thirteen".