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130210442231 is a prime number
BaseRepresentation
bin111100101000100100…
…1011010101111110111
3110110002120220211002112
41321101021122233313
54113132333122411
6135452353401235
712256510332362
oct1712111325767
9413076824075
10130210442231
1150249444531
122129b26921b
13c381676a6c
1464334090d9
1535c1581b8b
hex1e5125abf7

130210442231 has 2 divisors, whose sum is σ = 130210442232. Its totient is φ = 130210442230.

The previous prime is 130210442213. The next prime is 130210442293. The reversal of 130210442231 is 132244012031.

Together with previous prime (130210442213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130210442231 - 226 = 130143333367 is a prime.

It is a super-2 number, since 2×1302104422312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130210442197 and 130210442206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130210492231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65105221115 + 65105221116.

It is an arithmetic number, because the mean of its divisors is an integer number (65105221116).

Almost surely, 2130210442231 is an apocalyptic number.

130210442231 is a deficient number, since it is larger than the sum of its proper divisors (1).

130210442231 is an equidigital number, since it uses as much as digits as its factorization.

130210442231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 130210442231 its reverse (132244012031), we get a palindrome (262454454262).

The spelling of 130210442231 in words is "one hundred thirty billion, two hundred ten million, four hundred forty-two thousand, two hundred thirty-one".