Base | Representation |
---|---|
bin | 11000010000001111… |
… | …11111000111010101 |
3 | 1020121110201011102101 |
4 | 30020013333013111 |
5 | 203131412310031 |
6 | 5552025442101 |
7 | 640451325346 |
oct | 141007770725 |
9 | 36543634371 |
10 | 13021213141 |
11 | 5582154182 |
12 | 2634940331 |
13 | 12c68bb361 |
14 | 8b74cc0cd |
15 | 513242361 |
hex | 3081ff1d5 |
13021213141 has 2 divisors, whose sum is σ = 13021213142. Its totient is φ = 13021213140.
The previous prime is 13021213081. The next prime is 13021213201. The reversal of 13021213141 is 14131212031.
It is a balanced prime because it is at equal distance from previous prime (13021213081) and next prime (13021213201).
It can be written as a sum of positive squares in only one way, i.e., 10324592100 + 2696621041 = 101610^2 + 51929^2 .
It is a cyclic number.
It is not a de Polignac number, because 13021213141 - 213 = 13021204949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13021213241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6510606570 + 6510606571.
It is an arithmetic number, because the mean of its divisors is an integer number (6510606571).
Almost surely, 213021213141 is an apocalyptic number.
It is an amenable number.
13021213141 is a deficient number, since it is larger than the sum of its proper divisors (1).
13021213141 is an equidigital number, since it uses as much as digits as its factorization.
13021213141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 13021213141 its reverse (14131212031), we get a palindrome (27152425172).
The spelling of 13021213141 in words is "thirteen billion, twenty-one million, two hundred thirteen thousand, one hundred forty-one".
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