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1302130312031 is a prime number
BaseRepresentation
bin10010111100101101000…
…000111100001101011111
311121111000200220111221202
4102330231000330031133
5132313230324441111
62434105043350115
7163035001013543
oct22745500741537
94544020814852
101302130312031
1146225968414a
1219044098233b
1395a375692c3
1447048485a23
1523d10e78b3b
hex12f2d03c35f

1302130312031 has 2 divisors, whose sum is σ = 1302130312032. Its totient is φ = 1302130312030.

The previous prime is 1302130312013. The next prime is 1302130312037.

1302130312031 is nontrivially palindromic in base 10.

Together with previous prime (1302130312013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 1302130312031 - 210 = 1302130311007 is a prime.

It is a super-2 number, since 2×13021303120312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1302130311994 and 1302130312012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1302130312037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651065156015 + 651065156016.

It is an arithmetic number, because the mean of its divisors is an integer number (651065156016).

Almost surely, 21302130312031 is an apocalyptic number.

1302130312031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302130312031 is an equidigital number, since it uses as much as digits as its factorization.

1302130312031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 20.

It can be divided in two parts, 1302130 and 312031, that added together give a palindrome (1614161).

The spelling of 1302130312031 in words is "one trillion, three hundred two billion, one hundred thirty million, three hundred twelve thousand, thirty-one".