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13021320233102 = 26510660116551
BaseRepresentation
bin1011110101111100001100…
…1010101100000010001110
31201002211022012021120212112
42331133003022230002032
53201320130434424402
643405524551104022
72512521311525366
oct275370312540216
951084265246775
1013021320233102
114170346896455
121563751972012
13735b9ca3356c
143303417b79a6
15178aab28ce52
hexbd7c32ac08e

13021320233102 has 4 divisors (see below), whose sum is σ = 19531980349656. Its totient is φ = 6510660116550.

The previous prime is 13021320233099. The next prime is 13021320233171. The reversal of 13021320233102 is 20133202312031.

13021320233102 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×130213202331022 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3255330058274 + ... + 3255330058277.

It is an arithmetic number, because the mean of its divisors is an integer number (4882995087414).

Almost surely, 213021320233102 is an apocalyptic number.

13021320233102 is a deficient number, since it is larger than the sum of its proper divisors (6510660116554).

13021320233102 is an equidigital number, since it uses as much as digits as its factorization.

13021320233102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6510660116553.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13021320233102 its reverse (20133202312031), we get a palindrome (33154522545133).

The spelling of 13021320233102 in words is "thirteen trillion, twenty-one billion, three hundred twenty million, two hundred thirty-three thousand, one hundred two".

Divisors: 1 2 6510660116551 13021320233102