Base | Representation |
---|---|
bin | 1011110101111100001100… |
… | …1010101100000010001110 |
3 | 1201002211022012021120212112 |
4 | 2331133003022230002032 |
5 | 3201320130434424402 |
6 | 43405524551104022 |
7 | 2512521311525366 |
oct | 275370312540216 |
9 | 51084265246775 |
10 | 13021320233102 |
11 | 4170346896455 |
12 | 1563751972012 |
13 | 735b9ca3356c |
14 | 3303417b79a6 |
15 | 178aab28ce52 |
hex | bd7c32ac08e |
13021320233102 has 4 divisors (see below), whose sum is σ = 19531980349656. Its totient is φ = 6510660116550.
The previous prime is 13021320233099. The next prime is 13021320233171. The reversal of 13021320233102 is 20133202312031.
13021320233102 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×130213202331022 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3255330058274 + ... + 3255330058277.
It is an arithmetic number, because the mean of its divisors is an integer number (4882995087414).
Almost surely, 213021320233102 is an apocalyptic number.
13021320233102 is a deficient number, since it is larger than the sum of its proper divisors (6510660116554).
13021320233102 is an equidigital number, since it uses as much as digits as its factorization.
13021320233102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6510660116553.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 13021320233102 its reverse (20133202312031), we get a palindrome (33154522545133).
The spelling of 13021320233102 in words is "thirteen trillion, twenty-one billion, three hundred twenty million, two hundred thirty-three thousand, one hundred two".
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