Base | Representation |
---|---|
bin | 111100101000101001… |
… | …1111110110011001101 |
3 | 110110002210010111121011 |
4 | 1321101103332303031 |
5 | 4113134040230331 |
6 | 135452533005221 |
7 | 12256543014523 |
oct | 1712123766315 |
9 | 413083114534 |
10 | 130213211341 |
11 | 5024aa65a54 |
12 | 212a0183811 |
13 | c3821062a5 |
14 | 643392a313 |
15 | 35c192c3b1 |
hex | 1e514feccd |
130213211341 has 2 divisors, whose sum is σ = 130213211342. Its totient is φ = 130213211340.
The previous prime is 130213211329. The next prime is 130213211353. The reversal of 130213211341 is 143112312031.
It is a balanced prime because it is at equal distance from previous prime (130213211329) and next prime (130213211353).
It can be written as a sum of positive squares in only one way, i.e., 90854619241 + 39358592100 = 301421^2 + 198390^2 .
It is a cyclic number.
It is not a de Polignac number, because 130213211341 - 215 = 130213178573 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130213211311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65106605670 + 65106605671.
It is an arithmetic number, because the mean of its divisors is an integer number (65106605671).
Almost surely, 2130213211341 is an apocalyptic number.
It is an amenable number.
130213211341 is a deficient number, since it is larger than the sum of its proper divisors (1).
130213211341 is an equidigital number, since it uses as much as digits as its factorization.
130213211341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 130213211341 its reverse (143112312031), we get a palindrome (273325523372).
The spelling of 130213211341 in words is "one hundred thirty billion, two hundred thirteen million, two hundred eleven thousand, three hundred forty-one".
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