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130213333301 = 559123289811
BaseRepresentation
bin111100101000101010…
…0011100100100110101
3110110002210100200220012
41321101110130210311
54113134103131201
6135452535350005
712256544033222
oct1712124344465
9413083320805
10130213333301
1150250039647
12212a0222305
13c38214995c
14643395c949
1535c19535bb
hex1e5151c935

130213333301 has 4 divisors (see below), whose sum is σ = 130236628704. Its totient is φ = 130190037900.

The previous prime is 130213333259. The next prime is 130213333337. The reversal of 130213333301 is 103333312031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130213333301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130213336301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11639315 + ... + 11650496.

It is an arithmetic number, because the mean of its divisors is an integer number (32559157176).

Almost surely, 2130213333301 is an apocalyptic number.

It is an amenable number.

130213333301 is a deficient number, since it is larger than the sum of its proper divisors (23295403).

130213333301 is an equidigital number, since it uses as much as digits as its factorization.

130213333301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23295402.

The product of its (nonzero) digits is 1458, while the sum is 23.

Adding to 130213333301 its reverse (103333312031), we get a palindrome (233546645332).

The spelling of 130213333301 in words is "one hundred thirty billion, two hundred thirteen million, three hundred thirty-three thousand, three hundred one".

Divisors: 1 5591 23289811 130213333301