13022000141 has 2 divisors, whose sum is σ = 13022000142. Its totient is φ = 13022000140.

The previous prime is 13022000129. The next prime is 13022000143. The reversal of 13022000141 is 14100022031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12756798916 + 265201225 = 112946^2 + 16285^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13022000141 is a prime.

Together with 13022000143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13022000143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511000070 + 6511000071.

It is an arithmetic number, because the mean of its divisors is an integer number (6511000071).

Almost surely, 2^13022000141 is an apocalyptic number.

It is an amenable number.

13022000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13022000141 is an equidigital number, since it uses as much as digits as its factorization.

13022000141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 13022000141 its reverse (14100022031), we get a palindrome (27122022172).

The spelling of 13022000141 in words is "thirteen billion, twenty-two million, one hundred forty-one", and thus it is an aban number.