13022001311 has 4 divisors (see below), whose sum is σ = 14205819624. Its totient is φ = 11838183000.

The previous prime is 13022001227. The next prime is 13022001313. The reversal of 13022001311 is 11310022031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13022001311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13022001313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 591909140 + ... + 591909161.

It is an arithmetic number, because the mean of its divisors is an integer number (3551454906).

Almost surely, 2^13022001311 is an apocalyptic number.

13022001311 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13022001311 is a deficient number, since it is larger than the sum of its proper divisors (1183818313).

13022001311 is a wasteful number, since it uses less digits than its factorization.

13022001311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1183818312.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 13022001311 its reverse (11310022031), we get a palindrome (24332023342).

The spelling of 13022001311 in words is "thirteen billion, twenty-two million, one thousand, three hundred eleven".