Base | Representation |
---|---|
bin | 1011110101111110110001… |
… | …1101011111111110110011 |
3 | 1201002220002110220022222212 |
4 | 2331133230131133332303 |
5 | 3201323040313432243 |
6 | 43410121420122335 |
7 | 2512544423310353 |
oct | 275375435377663 |
9 | 51086073808885 |
10 | 13022013030323 |
11 | 4170671966240 |
12 | 15639059963ab |
13 | 735c8042034b |
14 | 3303a97d8b63 |
15 | 178aebedb318 |
hex | bd7ec75ffb3 |
13022013030323 has 4 divisors (see below), whose sum is σ = 14205832396728. Its totient is φ = 11838193663920.
The previous prime is 13022013030311. The next prime is 13022013030361. The reversal of 13022013030323 is 32303031022031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13022013030323 - 24 = 13022013030307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13022013030373) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 591909683186 + ... + 591909683207.
It is an arithmetic number, because the mean of its divisors is an integer number (3551458099182).
Almost surely, 213022013030323 is an apocalyptic number.
13022013030323 is a deficient number, since it is larger than the sum of its proper divisors (1183819366405).
13022013030323 is a wasteful number, since it uses less digits than its factorization.
13022013030323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1183819366404.
The product of its (nonzero) digits is 1944, while the sum is 23.
Adding to 13022013030323 its reverse (32303031022031), we get a palindrome (45325044052354).
The spelling of 13022013030323 in words is "thirteen trillion, twenty-two billion, thirteen million, thirty thousand, three hundred twenty-three".
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