Base | Representation |
---|---|
bin | 111100101000110111… |
… | …0101011011111000000 |
3 | 110110010021022002002220 |
4 | 1321101232223133000 |
5 | 4113142333210422 |
6 | 135453343011040 |
7 | 12256656344226 |
oct | 1712156533700 |
9 | 413107262086 |
10 | 130220210112 |
11 | 50253a06263 |
12 | 212a2599a80 |
13 | c3836b6a85 |
14 | 643482cb16 |
15 | 35c2360e5c |
hex | 1e51bab7c0 |
130220210112 has 28 divisors (see below), whose sum is σ = 344540973096. Its totient is φ = 43406736640.
The previous prime is 130220210093. The next prime is 130220210119. The reversal of 130220210112 is 211012022031.
It is a super-2 number, since 2×1302202101122 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130220210091 and 130220210100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130220210119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 339114939 + ... + 339115322.
Almost surely, 2130220210112 is an apocalyptic number.
130220210112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
130220210112 is an abundant number, since it is smaller than the sum of its proper divisors (214320762984).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130220210112 is an equidigital number, since it uses as much as digits as its factorization.
130220210112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 678230276 (or 678230266 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 130220210112 its reverse (211012022031), we get a palindrome (341232232143).
The spelling of 130220210112 in words is "one hundred thirty billion, two hundred twenty million, two hundred ten thousand, one hundred twelve".
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