Base | Representation |
---|---|
bin | 10010111100110001111… |
… | …000100100000011100011 |
3 | 11121111020101121210112212 |
4 | 102330301320210003203 |
5 | 132313412233031034 |
6 | 2434121122312335 |
7 | 163040012246015 |
oct | 22746170440343 |
9 | 4544211553485 |
10 | 1302212002019 |
11 | 4622a07aa035 |
12 | 1904641b86ab |
13 | 95a4b46b986 |
14 | 4705526c1b5 |
15 | 23d182132ce |
hex | 12f31e240e3 |
1302212002019 has 2 divisors, whose sum is σ = 1302212002020. Its totient is φ = 1302212002018.
The previous prime is 1302212001971. The next prime is 1302212002033. The reversal of 1302212002019 is 9102002122031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1302212002019 - 232 = 1297917034723 is a prime.
It is a super-2 number, since 2×13022120020192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1302212001985 and 1302212002003.
It is not a weakly prime, because it can be changed into another prime (1302212002319) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651106001009 + 651106001010.
It is an arithmetic number, because the mean of its divisors is an integer number (651106001010).
Almost surely, 21302212002019 is an apocalyptic number.
1302212002019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302212002019 is an equidigital number, since it uses as much as digits as its factorization.
1302212002019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
The spelling of 1302212002019 in words is "one trillion, three hundred two billion, two hundred twelve million, two thousand, nineteen".
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