Base | Representation |
---|---|
bin | 1011110101111111010000… |
… | …0011011011100101011111 |
3 | 1201002220102100121002222001 |
4 | 2331133310003123211133 |
5 | 3201323320421224203 |
6 | 43410142210303131 |
7 | 2512550531124256 |
oct | 275376403334537 |
9 | 51086370532861 |
10 | 13022140414303 |
11 | 4170727860759 |
12 | 1563940587aa7 |
13 | 735ca0931197 |
14 | 3303bc6b779d |
15 | 178b0829e91d |
hex | bd7f40db95f |
13022140414303 has 2 divisors, whose sum is σ = 13022140414304. Its totient is φ = 13022140414302.
The previous prime is 13022140414289. The next prime is 13022140414319. The reversal of 13022140414303 is 30341404122031.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (30341404122031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13022140414303 is a prime.
It is a super-2 number, since 2×130221404143032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13022140414333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511070207151 + 6511070207152.
It is an arithmetic number, because the mean of its divisors is an integer number (6511070207152).
Almost surely, 213022140414303 is an apocalyptic number.
13022140414303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13022140414303 is an equidigital number, since it uses as much as digits as its factorization.
13022140414303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 13022140414303 its reverse (30341404122031), we get a palindrome (43363544536334).
The spelling of 13022140414303 in words is "thirteen trillion, twenty-two billion, one hundred forty million, four hundred fourteen thousand, three hundred three".
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