Search a number
-
+
130231003103 is a prime number
BaseRepresentation
bin111100101001001011…
…1110110011111011111
3110110011000121102022022
41321102113312133133
54113203114044403
6135454410210355
712260150155535
oct1712227663737
9413130542268
10130231003103
115025a008193
12212a61239bb
13c3859c5566
14643603c155
1535c3293d38
hex1e525f67df

130231003103 has 2 divisors, whose sum is σ = 130231003104. Its totient is φ = 130231003102.

The previous prime is 130231003051. The next prime is 130231003127. The reversal of 130231003103 is 301300132031.

It is a strong prime.

It is an emirp because it is prime and its reverse (301300132031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130231003103 - 214 = 130230986719 is a prime.

It is a super-2 number, since 2×1302310031032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130231003303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65115501551 + 65115501552.

It is an arithmetic number, because the mean of its divisors is an integer number (65115501552).

Almost surely, 2130231003103 is an apocalyptic number.

130231003103 is a deficient number, since it is larger than the sum of its proper divisors (1).

130231003103 is an equidigital number, since it uses as much as digits as its factorization.

130231003103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 130231003103 its reverse (301300132031), we get a palindrome (431531135134).

The spelling of 130231003103 in words is "one hundred thirty billion, two hundred thirty-one million, three thousand, one hundred three".