Base | Representation |
---|---|
bin | 111100101001001100… |
… | …1100001001101110111 |
3 | 110110011001102121221211 |
4 | 1321102121201031313 |
5 | 4113203222041442 |
6 | 135454423422251 |
7 | 12260153656156 |
oct | 1712231411567 |
9 | 413131377854 |
10 | 130231440247 |
11 | 5025a286667 |
12 | 212a62b4987 |
13 | c385b1951c |
14 | 643611359d |
15 | 35c332d617 |
hex | 1e52661377 |
130231440247 has 2 divisors, whose sum is σ = 130231440248. Its totient is φ = 130231440246.
The previous prime is 130231440239. The next prime is 130231440253. The reversal of 130231440247 is 742044132031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130231440247 - 23 = 130231440239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130231440217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65115720123 + 65115720124.
It is an arithmetic number, because the mean of its divisors is an integer number (65115720124).
Almost surely, 2130231440247 is an apocalyptic number.
130231440247 is a deficient number, since it is larger than the sum of its proper divisors (1).
130231440247 is an equidigital number, since it uses as much as digits as its factorization.
130231440247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 130231440247 its reverse (742044132031), we get a palindrome (872275572278).
The spelling of 130231440247 in words is "one hundred thirty billion, two hundred thirty-one million, four hundred forty thousand, two hundred forty-seven".
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