Base | Representation |
---|---|
bin | 10010111100111000111… |
… | …011001100101100111111 |
3 | 11121111112121220111012220 |
4 | 102330320323030230333 |
5 | 132314133003231221 |
6 | 2434140542300423 |
7 | 163042645325064 |
oct | 22747073145477 |
9 | 4544477814186 |
10 | 1302330133311 |
11 | 4623514548a9 |
12 | 190497887713 |
13 | 95a69a9014c |
14 | 47066c1cc6b |
15 | 23d2379a0c6 |
hex | 12f38eccb3f |
1302330133311 has 4 divisors (see below), whose sum is σ = 1736440177752. Its totient is φ = 868220088872.
The previous prime is 1302330133309. The next prime is 1302330133327. The reversal of 1302330133311 is 1133310332031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1302330133311 - 21 = 1302330133309 is a prime.
It is a super-2 number, since 2×13023301333112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1302330133361) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217055022216 + ... + 217055022221.
It is an arithmetic number, because the mean of its divisors is an integer number (434110044438).
Almost surely, 21302330133311 is an apocalyptic number.
1302330133311 is a deficient number, since it is larger than the sum of its proper divisors (434110044441).
1302330133311 is an equidigital number, since it uses as much as digits as its factorization.
1302330133311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 434110044440.
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 1302330133311 its reverse (1133310332031), we get a palindrome (2435640465342).
The spelling of 1302330133311 in words is "one trillion, three hundred two billion, three hundred thirty million, one hundred thirty-three thousand, three hundred eleven".
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