13024113 has 4 divisors (see below), whose sum is σ = 17365488. Its totient is φ = 8682740.

The previous prime is 13024087. The next prime is 13024117. The reversal of 13024113 is 31142031.

13024113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31142031 = 3 ⋅10380677.

It is a cyclic number.

It is not a de Polignac number, because 13024113 - 2¹² = 13020017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13024092 and 13024101.

It is not an unprimeable number, because it can be changed into a prime (13024117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2170683 + ... + 2170688.

It is an arithmetic number, because the mean of its divisors is an integer number (4341372).

Almost surely, 2^13024113 is an apocalyptic number.

It is an amenable number.

13024113 is a deficient number, since it is larger than the sum of its proper divisors (4341375).

13024113 is an equidigital number, since it uses as much as digits as its factorization.

13024113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4341374.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 13024113 is about 3608.8935977665. The cubic root of 13024113 is about 235.2787577829.

Adding to 13024113 its reverse (31142031), we get a palindrome (44166144).

The spelling of 13024113 in words is "thirteen million, twenty-four thousand, one hundred thirteen".