Base | Representation |
---|---|
bin | 11101100111010101100000… |
… | …100000101100000111010011 |
3 | 122002011102222200211100021021 |
4 | 131213111200200230013103 |
5 | 114032424314110330420 |
6 | 1141002230040340311 |
7 | 36301666514624536 |
oct | 3547254040540723 |
9 | 562142880740237 |
10 | 130246502433235 |
11 | 38556260116831 |
12 | 1273678a174697 |
13 | 578a266b4a136 |
14 | 2423d70286a1d |
15 | 100d0252d67aa |
hex | 76756082c1d3 |
130246502433235 has 4 divisors (see below), whose sum is σ = 156295802919888. Its totient is φ = 104197201946584.
The previous prime is 130246502433217. The next prime is 130246502433239. The reversal of 130246502433235 is 532334205642031.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130246502433235 - 233 = 130237912498643 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130246502433191 and 130246502433200.
It is not an unprimeable number, because it can be changed into a prime (130246502433239) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13024650243319 + ... + 13024650243328.
It is an arithmetic number, because the mean of its divisors is an integer number (39073950729972).
Almost surely, 2130246502433235 is an apocalyptic number.
130246502433235 is a deficient number, since it is larger than the sum of its proper divisors (26049300486653).
130246502433235 is an equidigital number, since it uses as much as digits as its factorization.
130246502433235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26049300486652.
The product of its (nonzero) digits is 1555200, while the sum is 43.
The spelling of 130246502433235 in words is "one hundred thirty trillion, two hundred forty-six billion, five hundred two million, four hundred thirty-three thousand, two hundred thirty-five".
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