13026113437 has 2 divisors, whose sum is σ = 13026113438. Its totient is φ = 13026113436.

The previous prime is 13026113407. The next prime is 13026113489. The reversal of 13026113437 is 73431162031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6519916516 + 6506196921 = 80746^2 + 80661^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13026113437 is a prime.

It is a super-3 number, since 3×13026113437³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13026113399 and 13026113408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13026113407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6513056718 + 6513056719.

It is an arithmetic number, because the mean of its divisors is an integer number (6513056719).

Almost surely, 2^13026113437 is an apocalyptic number.

It is an amenable number.

13026113437 is a deficient number, since it is larger than the sum of its proper divisors (1).

13026113437 is an equidigital number, since it uses as much as digits as its factorization.

13026113437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9072, while the sum is 31.

Adding to 13026113437 its reverse (73431162031), we get a palindrome (86457275468).

The spelling of 13026113437 in words is "thirteen billion, twenty-six million, one hundred thirteen thousand, four hundred thirty-seven".