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13026113489 is a prime number
BaseRepresentation
bin11000010000110101…
…01011011111010001
31020121210221010102202
430020122223133101
5203134141112424
65552322452545
7640541065154
oct141032533721
936553833382
1013026113489
1155849a0954
122636504155
1312c791597c
148b8005c9b
155138ae2ae
hex3086ab7d1

13026113489 has 2 divisors, whose sum is σ = 13026113490. Its totient is φ = 13026113488.

The previous prime is 13026113437. The next prime is 13026113593. The reversal of 13026113489 is 98431162031.

13026113489 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11484765889 + 1541347600 = 107167^2 + 39260^2 .

It is an emirp because it is prime and its reverse (98431162031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13026113489 is a prime.

It is not a weakly prime, because it can be changed into another prime (13026113189) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6513056744 + 6513056745.

It is an arithmetic number, because the mean of its divisors is an integer number (6513056745).

Almost surely, 213026113489 is an apocalyptic number.

It is an amenable number.

13026113489 is a deficient number, since it is larger than the sum of its proper divisors (1).

13026113489 is an equidigital number, since it uses as much as digits as its factorization.

13026113489 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 38.

The spelling of 13026113489 in words is "thirteen billion, twenty-six million, one hundred thirteen thousand, four hundred eighty-nine".