Base | Representation |
---|---|
bin | 1011110110011100100000… |
… | …0101001011111101011111 |
3 | 1201010122200120220001210002 |
4 | 2331213020011023331133 |
5 | 3201440411102033204 |
6 | 43413521310204515 |
7 | 2513246235526061 |
oct | 275471005137537 |
9 | 51118616801702 |
10 | 13029992611679 |
11 | 4173a9715787a |
12 | 15653721b373b |
13 | 736952664614 |
14 | 3309254a9731 |
15 | 178e1780191e |
hex | bd9c814bf5f |
13029992611679 has 2 divisors, whose sum is σ = 13029992611680. Its totient is φ = 13029992611678.
The previous prime is 13029992611651. The next prime is 13029992611681. The reversal of 13029992611679 is 97611629992031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13029992611679 - 240 = 11930480983903 is a prime.
Together with 13029992611681, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13029992611379) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6514996305839 + 6514996305840.
It is an arithmetic number, because the mean of its divisors is an integer number (6514996305840).
Almost surely, 213029992611679 is an apocalyptic number.
13029992611679 is a deficient number, since it is larger than the sum of its proper divisors (1).
13029992611679 is an equidigital number, since it uses as much as digits as its factorization.
13029992611679 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19840464, while the sum is 65.
The spelling of 13029992611679 in words is "thirteen trillion, twenty-nine billion, nine hundred ninety-two million, six hundred eleven thousand, six hundred seventy-nine".
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