Search a number
-
+
1303102000000 = 27561016451
BaseRepresentation
bin10010111101100110111…
…011101000101110000000
311121120112102022101021001
4102331212323220232000
5132322223103000000
62434345314141344
7163101040146223
oct22754673505600
94546472271231
101303102000000
1146270811a759
12190672281854
1395b609728b8
14470db5435ba
1523d6b41646a
hex12f66ee8b80

1303102000000 has 224 divisors, whose sum is σ = 3277624452120. Its totient is φ = 516000000000.

The previous prime is 1303101999973. The next prime is 1303102000021. The reversal of 1303102000000 is 2013031.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 201996775 + ... + 202003225.

Almost surely, 21303102000000 is an apocalyptic number.

1303102000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1303102000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1638812226060).

1303102000000 is an abundant number, since it is smaller than the sum of its proper divisors (1974522452120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1303102000000 is an frugal number, since it uses more digits than its factorization.

1303102000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6596 (or 6559 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 10.

Adding to 1303102000000 its reverse (2013031), we get a palindrome (1303104013031).

The spelling of 1303102000000 in words is "one trillion, three hundred three billion, one hundred two million", and thus it is an aban number.