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130310213207 is a prime number
BaseRepresentation
bin111100101011100011…
…0000000111001010111
3110110100112122201010212
41321113012000321113
54113333403310312
6135510320040035
712262131352016
oct1712706007127
9413315581125
10130310213207
115029a799989
122130876301b
13c39923a245
14644277aa7d
1535ca1dd822
hex1e57180e57

130310213207 has 2 divisors, whose sum is σ = 130310213208. Its totient is φ = 130310213206.

The previous prime is 130310213177. The next prime is 130310213213. The reversal of 130310213207 is 702312013031.

It is a strong prime.

It is an emirp because it is prime and its reverse (702312013031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130310213207 - 212 = 130310209111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130310213107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65155106603 + 65155106604.

It is an arithmetic number, because the mean of its divisors is an integer number (65155106604).

Almost surely, 2130310213207 is an apocalyptic number.

130310213207 is a deficient number, since it is larger than the sum of its proper divisors (1).

130310213207 is an equidigital number, since it uses as much as digits as its factorization.

130310213207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 23.

Adding to 130310213207 its reverse (702312013031), we get a palindrome (832622226238).

The spelling of 130310213207 in words is "one hundred thirty billion, three hundred ten million, two hundred thirteen thousand, two hundred seven".