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130311201281 is a prime number
BaseRepresentation
bin111100101011100100…
…1110010001000000001
3110110100121111220112012
41321113021302020001
54113334131420111
6135510353142305
712262142635502
oct1712711621001
9413317456465
10130311201281
11502a0304278
1221308b5a995
13c3994c4bc1
146442956ba9
1535ca33648b
hex1e57272201

130311201281 has 2 divisors, whose sum is σ = 130311201282. Its totient is φ = 130311201280.

The previous prime is 130311201217. The next prime is 130311201313. The reversal of 130311201281 is 182102113031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95471112256 + 34840089025 = 308984^2 + 186655^2 .

It is an emirp because it is prime and its reverse (182102113031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130311201281 - 26 = 130311201217 is a prime.

It is a super-2 number, since 2×1303112012812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130311201781) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65155600640 + 65155600641.

It is an arithmetic number, because the mean of its divisors is an integer number (65155600641).

Almost surely, 2130311201281 is an apocalyptic number.

It is an amenable number.

130311201281 is a deficient number, since it is larger than the sum of its proper divisors (1).

130311201281 is an equidigital number, since it uses as much as digits as its factorization.

130311201281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 23.

The spelling of 130311201281 in words is "one hundred thirty billion, three hundred eleven million, two hundred one thousand, two hundred eighty-one".