| Base | Representation |
|---|---|
| bin | 1011110110100000101101… |
| … | …0110011101011001001000 |
| 3 | 1201010202121020112221202000 |
| 4 | 2331220023112131121020 |
| 5 | 3202000214012304000 |
| 6 | 43414225304111000 |
| 7 | 2513316221503662 |
| oct | 275501326353110 |
| 9 | 51122536487660 |
| 10 | 13031121213000 |
| 11 | 4174516227740 |
| 12 | 1565628165460 |
| 13 | 736aa241a757 |
| 14 | 3309d1331532 |
| 15 | 178e81937000 |
| hex | bda0b59d648 |
13031121213000 has 512 divisors, whose sum is σ = 49339799308800. Its totient is φ = 3155311872000.
The previous prime is 13031121212999. The next prime is 13031121213041. The reversal of 13031121213000 is 31212113031.
13031121213000 is a `hidden beast` number, since 1 + 30 + 311 + 2 + 1 + 21 + 300 + 0 = 666.
13031121213000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 254503402 + ... + 254554598.
It is an arithmetic number, because the mean of its divisors is an integer number (96366795525).
Almost surely, 213031121213000 is an apocalyptic number.
13031121213000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13031121213000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24669899654400).
13031121213000 is an abundant number, since it is smaller than the sum of its proper divisors (36308678095800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13031121213000 is a wasteful number, since it uses less digits than its factorization.
13031121213000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52095 (or 52075 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 13031121213000 its reverse (31212113031), we get a palindrome (13062333326031).
It can be divided in two parts, 130311 and 21213000, that added together give a triangular number (21343311 = T6533).
The spelling of 13031121213000 in words is "thirteen trillion, thirty-one billion, one hundred twenty-one million, two hundred thirteen thousand".
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