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13031206422 = 2313167066749
BaseRepresentation
bin11000010001011100…
…00110111000010110
31020122011111212121220
430020232012320112
5203141442101142
65553023551210
7640632266313
oct141056067026
936564455556
1013031206422
11558785a293
12263815b506
1312c89a9b40
148b896dd0a
155140682ec
hex308b86e16

13031206422 has 16 divisors (see below), whose sum is σ = 28067214000. Its totient is φ = 4009601952.

The previous prime is 13031206387. The next prime is 13031206427. The reversal of 13031206422 is 22460213031.

It is a junction number, because it is equal to n+sod(n) for n = 13031206392 and 13031206401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13031206427) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 83533297 + ... + 83533452.

It is an arithmetic number, because the mean of its divisors is an integer number (1754200875).

Almost surely, 213031206422 is an apocalyptic number.

13031206422 is an abundant number, since it is smaller than the sum of its proper divisors (15036007578).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13031206422 is a wasteful number, since it uses less digits than its factorization.

13031206422 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 167066767.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 13031206422 its reverse (22460213031), we get a palindrome (35491419453).

It can be divided in two parts, 13031 and 206422, that added together give a triangular number (219453 = T662).

The spelling of 13031206422 in words is "thirteen billion, thirty-one million, two hundred six thousand, four hundred twenty-two".

Divisors: 1 2 3 6 13 26 39 78 167066749 334133498 501200247 1002400494 2171867737 4343735474 6515603211 13031206422