Base | Representation |
---|---|
bin | 1011110110100001000010… |
… | …1101010110111110110100 |
3 | 1201010202211111200210110010 |
4 | 2331220100231112332310 |
5 | 3202000410020232012 |
6 | 43414242234500220 |
7 | 2513321362525266 |
oct | 275502055267664 |
9 | 51122744623403 |
10 | 13031211102132 |
11 | 4174561a42783 |
12 | 1565652294670 |
13 | 736ab7c310a2 |
14 | 3309dd24db36 |
15 | 178e89790c3c |
hex | bda10b56fb4 |
13031211102132 has 24 divisors (see below), whose sum is σ = 30478382906272. Its totient is φ = 4333419367200.
The previous prime is 13031211102113. The next prime is 13031211102137. The reversal of 13031211102132 is 23120111213031.
It is a junction number, because it is equal to n+sod(n) for n = 13031211102099 and 13031211102108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13031211102137) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1289703094 + ... + 1289713197.
Almost surely, 213031211102132 is an apocalyptic number.
13031211102132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13031211102132 is an abundant number, since it is smaller than the sum of its proper divisors (17447171804140).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13031211102132 is a wasteful number, since it uses less digits than its factorization.
13031211102132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2579416719 (or 2579416717 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 13031211102132 its reverse (23120111213031), we get a palindrome (36151322315163).
The spelling of 13031211102132 in words is "thirteen trillion, thirty-one billion, two hundred eleven million, one hundred two thousand, one hundred thirty-two".
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