13031422241333 has 8 divisors (see below), whose sum is σ = 13176076844952. Its totient is φ = 12886978046976.

The previous prime is 13031422241323. The next prime is 13031422241377. The reversal of 13031422241333 is 33314222413031.

It can be written as a sum of positive squares in 4 ways, for example, as 1110195180964 + 11921227060369 = 1053658^2 + 3452713^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13031422241333 - 2¹⁸ = 13031421979189 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13031422241333.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13031422241323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52477760 + ... + 52725497.

It is an arithmetic number, because the mean of its divisors is an integer number (1647009605619).

Almost surely, 2^{13031422241333} is an apocalyptic number.

It is an amenable number.

13031422241333 is a deficient number, since it is larger than the sum of its proper divisors (144654603619).

13031422241333 is a wasteful number, since it uses less digits than its factorization.

13031422241333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105204631.

The product of its (nonzero) digits is 31104, while the sum is 32.

Adding to 13031422241333 its reverse (33314222413031), we get a palindrome (46345644654364).

The spelling of 13031422241333 in words is "thirteen trillion, thirty-one billion, four hundred twenty-two million, two hundred forty-one thousand, three hundred thirty-three".