130315121 has 2 divisors, whose sum is σ = 130315122. Its totient is φ = 130315120.

The previous prime is 130315117. The next prime is 130315123. The reversal of 130315121 is 121513031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126315121 + 4000000 = 11239^2 + 2000^2 .

It is a cyclic number.

It is not a de Polignac number, because 130315121 - 2² = 130315117 is a prime.

It is a super-2 number, since 2×130315121² = 33964061522489282, which contains 22 as substring.

Together with 130315123, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130315121.

It is not a weakly prime, because it can be changed into another prime (130315123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65157560 + 65157561.

It is an arithmetic number, because the mean of its divisors is an integer number (65157561).

Almost surely, 2^130315121 is an apocalyptic number.

It is an amenable number.

130315121 is a deficient number, since it is larger than the sum of its proper divisors (1).

130315121 is an equidigital number, since it uses as much as digits as its factorization.

130315121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 130315121 is about 11415.5648568084. The cubic root of 130315121 is about 506.9886893231.

Adding to 130315121 its reverse (121513031), we get a palindrome (251828152).

The spelling of 130315121 in words is "one hundred thirty million, three hundred fifteen thousand, one hundred twenty-one".