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13032021330110 = 2511287115460453
BaseRepresentation
bin1011110110100100000100…
…0000001000100010111110
31201010211220222021122021202
42331221001000020202332
53202004034430030420
643414454500455502
72513350431411056
oct275510100104276
951124828248252
1013032021330110
114174938329a82
1215658396aa592
13736bb6a55523
14330a78abc566
15178ed5988575
hexbda410088be

13032021330110 has 16 divisors (see below), whose sum is σ = 23459716885536. Its totient is φ = 5212346645088.

The previous prime is 13032021330109. The next prime is 13032021330121. The reversal of 13032021330110 is 1103312023031.

It is a super-3 number, since 3×130320213301103 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57617357 + ... + 57843096.

It is an arithmetic number, because the mean of its divisors is an integer number (1466232305346).

Almost surely, 213032021330110 is an apocalyptic number.

13032021330110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13032021330110 is a deficient number, since it is larger than the sum of its proper divisors (10427695555426).

13032021330110 is a wasteful number, since it uses less digits than its factorization.

13032021330110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 115471747.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 13032021330110 its reverse (1103312023031), we get a palindrome (14135333353141).

The spelling of 13032021330110 in words is "thirteen trillion, thirty-two billion, twenty-one million, three hundred thirty thousand, one hundred ten".

Divisors: 1 2 5 10 11287 22574 56435 112870 115460453 230920906 577302265 1154604530 1303202133011 2606404266022 6516010665055 13032021330110