Base | Representation |
---|---|
bin | 10010111101101101011… |
… | …111010010001010110101 |
3 | 11121120211002022101000202 |
4 | 102331231133102022311 |
5 | 132322434233224432 |
6 | 2434404244050245 |
7 | 163103544203465 |
oct | 22755537221265 |
9 | 4546732271022 |
10 | 1303212008117 |
11 | 462764227458 |
12 | 1906a3093985 |
13 | 95b7a6ab866 |
14 | 4710bdbbba5 |
15 | 23d75de6462 |
hex | 12f6d7d22b5 |
1303212008117 has 2 divisors, whose sum is σ = 1303212008118. Its totient is φ = 1303212008116.
The previous prime is 1303212008101. The next prime is 1303212008143. The reversal of 1303212008117 is 7118002123031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1224178493476 + 79033514641 = 1106426^2 + 281129^2 .
It is a cyclic number.
It is not a de Polignac number, because 1303212008117 - 24 = 1303212008101 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1303212008117.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1303212002117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651606004058 + 651606004059.
It is an arithmetic number, because the mean of its divisors is an integer number (651606004059).
Almost surely, 21303212008117 is an apocalyptic number.
It is an amenable number.
1303212008117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303212008117 is an equidigital number, since it uses as much as digits as its factorization.
1303212008117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 29.
The spelling of 1303212008117 in words is "one trillion, three hundred three billion, two hundred twelve million, eight thousand, one hundred seventeen".
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