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13032212012341 is a prime number
BaseRepresentation
bin1011110110100100110001…
…0111100001110100110101
31201010212102021002022010121
42331221030113201310311
53202004432233343331
643414525431451541
72513355235236664
oct275511427416465
951125367068117
1013032212012341
114174a25a283a5
121565891526bb1
13736c173c9652
14330a96156ddb
15178ee75a1c11
hexbda4c5e1d35

13032212012341 has 2 divisors, whose sum is σ = 13032212012342. Its totient is φ = 13032212012340.

The previous prime is 13032212012293. The next prime is 13032212012357. The reversal of 13032212012341 is 14321021223031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9560123883025 + 3472088129316 = 3091945^2 + 1863354^2 .

It is a cyclic number.

It is not a de Polignac number, because 13032212012341 - 27 = 13032212012213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13032212712341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516106006170 + 6516106006171.

It is an arithmetic number, because the mean of its divisors is an integer number (6516106006171).

Almost surely, 213032212012341 is an apocalyptic number.

It is an amenable number.

13032212012341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13032212012341 is an equidigital number, since it uses as much as digits as its factorization.

13032212012341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13032212012341 its reverse (14321021223031), we get a palindrome (27353233235372).

The spelling of 13032212012341 in words is "thirteen trillion, thirty-two billion, two hundred twelve million, twelve thousand, three hundred forty-one".