Base | Representation |
---|---|
bin | 1011110110100100110001… |
… | …0111100001110100000101 |
3 | 1201010212102021002022001211 |
4 | 2331221030113201310011 |
5 | 3202004432233343133 |
6 | 43414525431451421 |
7 | 2513355235236565 |
oct | 275511427416405 |
9 | 51125367068054 |
10 | 13032212012293 |
11 | 4174a25a28361 |
12 | 1565891526b71 |
13 | 736c173c9616 |
14 | 330a96156da5 |
15 | 178ee75a1bcd |
hex | bda4c5e1d05 |
13032212012293 has 2 divisors, whose sum is σ = 13032212012294. Its totient is φ = 13032212012292.
The previous prime is 13032212012291. The next prime is 13032212012341. The reversal of 13032212012293 is 39221021223031.
13032212012293 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8904029217444 + 4128182794849 = 2983962^2 + 2031793^2 .
It is a cyclic number.
It is not a de Polignac number, because 13032212012293 - 21 = 13032212012291 is a prime.
Together with 13032212012291, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13032212012291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516106006146 + 6516106006147.
It is an arithmetic number, because the mean of its divisors is an integer number (6516106006147).
Almost surely, 213032212012293 is an apocalyptic number.
It is an amenable number.
13032212012293 is a deficient number, since it is larger than the sum of its proper divisors (1).
13032212012293 is an equidigital number, since it uses as much as digits as its factorization.
13032212012293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 31.
The spelling of 13032212012293 in words is "thirteen trillion, thirty-two billion, two hundred twelve million, twelve thousand, two hundred ninety-three".
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