Base | Representation |
---|---|
bin | 10010111101101110000… |
… | …101110111001001011101 |
3 | 11121120211210100011100221 |
4 | 102331232011313021131 |
5 | 132322444330333203 |
6 | 2434405244521341 |
7 | 163104026153326 |
oct | 22755605671135 |
9 | 4546753304327 |
10 | 1303222121053 |
11 | 462769a04456 |
12 | 1906a6550251 |
13 | 95b7c80c948 |
14 | 4710d49144d |
15 | 23d76c42abd |
hex | 12f6e17725d |
1303222121053 has 2 divisors, whose sum is σ = 1303222121054. Its totient is φ = 1303222121052.
The previous prime is 1303222121009. The next prime is 1303222121059. The reversal of 1303222121053 is 3501212223031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1032211296484 + 271010824569 = 1015978^2 + 520587^2 .
It is an emirp because it is prime and its reverse (3501212223031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1303222121053 - 237 = 1165783167581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1303222121059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651611060526 + 651611060527.
It is an arithmetic number, because the mean of its divisors is an integer number (651611060527).
Almost surely, 21303222121053 is an apocalyptic number.
It is an amenable number.
1303222121053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303222121053 is an equidigital number, since it uses as much as digits as its factorization.
1303222121053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 1303222121053 its reverse (3501212223031), we get a palindrome (4804434344084).
The spelling of 1303222121053 in words is "one trillion, three hundred three billion, two hundred twenty-two million, one hundred twenty-one thousand, fifty-three".
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