13033000110133 has 4 divisors (see below), whose sum is σ = 13054758040800. Its totient is φ = 13011242179468.

The previous prime is 13033000110113. The next prime is 13033000110203. The reversal of 13033000110133 is 33101100033031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13033000110133 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13033000110133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13033000110113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10878964435 + ... + 10878965632.

It is an arithmetic number, because the mean of its divisors is an integer number (3263689510200).

Almost surely, 2^{13033000110133} is an apocalyptic number.

It is an amenable number.

13033000110133 is a deficient number, since it is larger than the sum of its proper divisors (21757930667).

13033000110133 is an equidigital number, since it uses as much as digits as its factorization.

13033000110133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21757930666.

The product of its (nonzero) digits is 243, while the sum is 19.

Adding to 13033000110133 its reverse (33101100033031), we get a palindrome (46134100143164).

The spelling of 13033000110133 in words is "thirteen trillion, thirty-three billion, one hundred ten thousand, one hundred thirty-three".